Find the equation of the circle whose centre is at `(3,-1)` and which cuts off a chord of length `6u n i t s` on the line `2x-5y+18=0.`

Explanation

To find the equation of the circle whose center is at (3, -1) and which cuts off a chord of length 6 units on the line given by the equation \(2x - 5y + 18 = 0\), we will follow these steps:

### Step 1: Identify the center of the circle and the line equation
The center of the circle is given as \(C(3, -1)\) and the line equation is \(2x - 5y + 18 = 0\).

### Step 2: Find the distance from the center to the line
To find the distance \(d\) from the center \(C(3, -1)\) to the line \(2x - 5y + 18 = 0\), we use the formula for the distance from a point \((x_0, y_0)\) to a line \(Ax + By + C = 0\):

...