Find the equation of the circle passing through the point (7, 3) having radius 3 units and whose centre lies on the line `y = x-1`

Explanation

To find the equation of the circle passing through the point (7, 3) with a radius of 3 units and whose center lies on the line \( y = x - 1 \), we can follow these steps:

### Step 1: General Equation of the Circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
Here, we know \(r = 3\), so \(r^2 = 9\).
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