Home
Class 11
MATHS
. The shortest distance from the point (...

. The shortest distance from the point (2, -7) to circle `x^2+y^2-14x-10y-151=0`

Text Solution

AI Generated Solution

To find the shortest distance from the point (2, -7) to the circle given by the equation \(x^2 + y^2 - 14x - 10y - 151 = 0\), we can follow these steps: ### Step 1: Rewrite the Circle's Equation First, we need to rewrite the equation of the circle in standard form. The given equation is: \[ x^2 + y^2 - 14x - 10y - 151 = 0 \] ...
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|6 Videos

  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Objective type|13 Videos

  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Long answer|10 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NCERT EXEMPLAR ENGLISH|Exercise OBJECTIVE TYPE QUESTIONS|16 Videos

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|16 Videos

Similar Questions

Explore conceptually related problems

Find the greatest distance of the point P(10 ,7) from the circle x^2+y^2-4x-2y-20=0

Let P be the point on parabola y^2=4x which is at the shortest distance from the center S of the circle x^2+y^2-4x-16y+64=0 let Q be the point on the circle dividing the line segment SP internally. Then

Let P be the point on the parabola y^2=4x which is at the shortest distance from the center S of the circle x^2+y^2−4x−16y+64=0 . Let Q be the point on the circle dividing the line segment SP internally. Then

The shortest distance of the point (1, 3, 5) from x^(2) + y^(2) = 0 is

The shortest distance of (-5,4) to the circle x^(2)+y^(2)-6x+4y-12=0 is

The shortest distance from the line 3x+4y=25 to the circle x^2+y^2=6x-8y is equal to :

The sum of the minimum and maximum distances of the point (4,-3) to the circle x^2 +y^2+4x-10y-7=0 a) 10 b) 12 c) 16 d) 20

The shortest distance of the point (8,1) from the circle (x + 2)^(2) + (y - 1)^(2) = 25 is

The maximum distance of the point (4,4) from the circle x^2+y^2-2x-15=0 is

The shortest distance from the point (0, 5) to the circumference of the circle x^2 + y^2 - 10x + 14y - 151 = 0 is: (A) 13 (B) 9 (C) 2 (D) 5