Check wheather The point (1,2) lies inside the circle `x^(2)+y^(2)-2x+6y+1=0`.

Explanation

To determine whether the point (1, 2) lies inside the circle defined by the equation \( x^2 + y^2 - 2x + 6y + 1 = 0 \), we can follow these steps:

### Step 1: Rewrite the Circle Equation
The equation of the circle is given as:
\[ x^2 + y^2 - 2x + 6y + 1 = 0 \]

### Step 2: Identify the Point
We need to check the point \( (x_1, y_1) = (1, 2) \).
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