Home
Class 11
MATHS
The locus of the point of intersection o...

The locus of the point of intersection of lines `sqrt3x-y-4sqrt(3k)`=0 and `sqrt3kx+ky-4sqrt3=0` for different value of k is a hyperbola whose eccentricity is 2.

Text Solution

AI Generated Solution

To find the locus of the point of intersection of the lines given by the equations \( \sqrt{3}x - y - 4\sqrt{3}k = 0 \) and \( \sqrt{3}kx + ky - 4\sqrt{3} = 0 \) for different values of \( k \), we will follow these steps: ### Step 1: Express \( k \) in terms of \( x \) and \( y \) from the first equation. From the first equation: \[ \sqrt{3}x - y - 4\sqrt{3}k = 0 \] Rearranging gives: ...
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|6 Videos
  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Objective type|13 Videos
  • CONIC SECTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Long answer|10 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NCERT EXEMPLAR ENGLISH|Exercise OBJECTIVE TYPE QUESTIONS|16 Videos
  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|16 Videos

Similar Questions

Explore conceptually related problems

Prove that the locus of the point of intersection of the lines sqrt3 x -y -4 sqrt3 k =0 and sqrt3 k x+ ky - 4 sqrt3 =0, for different values of k, is a hyperbola whose eccentricity is 2.

The locus of the point of intersection of the lines sqrt3 x- y-4sqrt3 t= 0 & sqrt3 tx +ty-4 sqrt3=0 (where t is a parameter) is a hyperbola whose eccentricity is:

The locus of the point of intersection of the lines sqrt3 x- y-4sqrt3 t= 0 & sqrt3 tx +ty-4 sqrt3=0 (where t is a parameter) is a hyperbola whose eccentricity is: (a) sqrt3 (b) 2 (c) 2/sqrt3 (d) 4/3

The locus of the point of intersection of the lines sqrt(3)x-y-4sqrt(3)lambda=0\ a n d\ sqrt(3)lambdax+lambday-4sqrt(3)=0 is a hyperbola of eccentricity a. 1 b. 2 c. 3 d. 4

Find the locus of the point of intersection of the lines sqrt(3x)-y-4sqrt(3lambda)=0a n dsqrt(3)lambdax+lambday-4sqrt(3)=0 for different values of lambdadot

The locus of the point of intersection of the lines, sqrt(2)x-y+4sqrt(2)k=0" and "sqrt(2)kx+ky-4sqrt(2)=0 (k is any non-zero real parameter), is:

Find the angle between the lines y-sqrt(3)x-5=0 and sqrt(3)y-x+6=0 .

Solve the following system of equations: sqrt(2)x-sqrt(3)y=0,\ \ \ \ sqrt(3)x-sqrt(8)y=0

Solve the following system of equations: sqrt(2)x-sqrt(3)y=0,\ \ \ \ sqrt(3)x-sqrt(8)y=0

(v) Solve for x and y if (sqrt2 x+sqrt 3 y)=0 and (sqrt3 x- sqrt8 y)=0