The equation of the hyperbola with vertices at (0,`pm`6) and eccentricity 5/3 is….. And its foci are …….

Explanation

To find the equation of the hyperbola with vertices at (0, ±6) and eccentricity 5/3, we can follow these steps:

### Step 1: Identify the coordinates of the vertices
The vertices of the hyperbola are given as (0, ±6). This indicates that the hyperbola opens vertically, which means it is centered at the origin (0, 0).

### Step 2: Determine the value of b
From the vertices (0, ±6), we can identify that:
- The distance from the center to each vertex is \( b = 6 \).
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