In a Young's double slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case

Options

A. there shall be alternate interference pattersn of red and blue
B. there shall be an interface pattern for red distinct from that for blue
C. there shall be no interface frings
D. there shall be no interface pattern for red mixing with one for blue

Explanation

To solve the problem, we need to analyze the situation described in the Young's double slit experiment with white light and colored filters.

### Step-by-Step Solution:

1. **Understanding the Setup**: In a Young's double slit experiment, we typically have a coherent light source illuminating two slits. Here, the source is white light, which contains all colors of the spectrum.

2. **Applying Filters**: One slit is covered with a red filter, and the other with a blue filter. The red filter allows only red light to pass through, while the blue filter allows only blue light to pass through.

3. **Effect of Filters on Light**: When white light passes through the red filter, it becomes monochromatic red light. Similarly, white light passing through the blue filter becomes monochromatic blue light.

4. **Coherence Condition**: For interference patterns to be formed, the light sources from both slits must be coherent. This means they should have the same wavelength, frequency, and a constant phase difference.

5. **Analyzing the Wavelengths**: Red light and blue light have different wavelengths and frequencies. Red light has a longer wavelength compared to blue light, which means they do not meet the coherence condition.

6. **Conclusion on Interference**: Since the two sources (red and blue light) are not coherent, they cannot produce an interference pattern. Therefore, no interference fringes will be observed on the screen.

7. **Final Answer**: The correct conclusion is that there shall be no interference fringes.