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The distance of the point P(-6,8) from t...

The distance of the point P(-6,8) from the origin is

A

8

B

`2sqrt(7)`

C

10

D

6

Text Solution

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The correct Answer is:
To find the distance of the point P(-6, 8) from the origin (0, 0), we can use the distance formula. The distance \( d \) from a point \( A(x, y) \) to the origin is given by the formula: \[ d = \sqrt{x^2 + y^2} \] ### Step-by-Step Solution: 1. **Identify the coordinates of point P**: The coordinates of point P are \( x = -6 \) and \( y = 8 \). 2. **Substitute the coordinates into the distance formula**: \[ d = \sqrt{(-6)^2 + (8)^2} \] 3. **Calculate the squares of the coordinates**: \[ (-6)^2 = 36 \quad \text{and} \quad (8)^2 = 64 \] 4. **Add the squares**: \[ 36 + 64 = 100 \] 5. **Take the square root of the sum**: \[ d = \sqrt{100} = 10 \] 6. **Conclusion**: The distance of point P from the origin is \( 10 \) units. ### Final Answer: The distance of the point P(-6, 8) from the origin is \( 10 \) units. ---

To find the distance of the point P(-6, 8) from the origin (0, 0), we can use the distance formula. The distance \( d \) from a point \( A(x, y) \) to the origin is given by the formula: \[ d = \sqrt{x^2 + y^2} \] ### Step-by-Step Solution: ...
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