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If a circle drawn with origin as the ce...

If a circle drawn with origin as the centre passes through `(13/(2),0)`, then the point which does not lie in the interior of the circle is

A

`((-3)/(4),1)`

B

`(2,(7)/(3))`

C

`(5,(-1)/(2))`

D

`(-6,(5)/(2))`

Text Solution

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The correct Answer is:
To solve the problem, we need to determine which point does not lie in the interior of a circle centered at the origin (0, 0) that passes through the point (13/2, 0). ### Step-by-Step Solution: 1. **Determine the Radius of the Circle**: The radius \( r \) of the circle can be calculated using the distance from the center (origin) to the point (13/2, 0). \[ r = \text{Distance from origin to } (13/2, 0) = \sqrt{(13/2 - 0)^2 + (0 - 0)^2} = \sqrt{(13/2)^2} = \frac{13}{2} \] 2. **Identify the Points to Check**: We need to check the distances of the given points from the origin to determine whether they lie inside, on, or outside the circle. The points are: - Option 1: \( (9/16, 1) \) - Option 2: \( (2, 7/3) \) - Option 3: \( (-3, 4) \) - Option 4: \( (-6, 5/2) \) 3. **Calculate the Distance for Each Point**: - **Option 1**: \[ d_1 = \sqrt{(9/16)^2 + 1^2} = \sqrt{\frac{81}{256} + 1} = \sqrt{\frac{81}{256} + \frac{256}{256}} = \sqrt{\frac{337}{256}} = \frac{\sqrt{337}}{16} \] - **Option 2**: \[ d_2 = \sqrt{2^2 + (7/3)^2} = \sqrt{4 + \frac{49}{9}} = \sqrt{\frac{36}{9} + \frac{49}{9}} = \sqrt{\frac{85}{9}} = \frac{\sqrt{85}}{3} \] - **Option 3**: \[ d_3 = \sqrt{(-3)^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] - **Option 4**: \[ d_4 = \sqrt{(-6)^2 + (5/2)^2} = \sqrt{36 + \frac{25}{4}} = \sqrt{\frac{144}{4} + \frac{25}{4}} = \sqrt{\frac{169}{4}} = \frac{13}{2} \] 4. **Compare Distances with the Radius**: - For **Option 1**: \(\frac{\sqrt{337}}{16} < \frac{13}{2}\) (inside the circle) - For **Option 2**: \(\frac{\sqrt{85}}{3} < \frac{13}{2}\) (inside the circle) - For **Option 3**: \(5 < \frac{13}{2}\) (inside the circle) - For **Option 4**: \(\frac{13}{2} = \frac{13}{2}\) (on the circle) 5. **Conclusion**: The point that does not lie in the interior of the circle is **Option 4**: \( (-6, 5/2) \) because it lies on the circle.

To solve the problem, we need to determine which point does not lie in the interior of a circle centered at the origin (0, 0) that passes through the point (13/2, 0). ### Step-by-Step Solution: 1. **Determine the Radius of the Circle**: The radius \( r \) of the circle can be calculated using the distance from the center (origin) to the point (13/2, 0). \[ r = \text{Distance from origin to } (13/2, 0) = \sqrt{(13/2 - 0)^2 + (0 - 0)^2} = \sqrt{(13/2)^2} = \frac{13}{2} ...
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