Find the ratio in which the line `2x+3y-5=0` divides the line segment joining the points (8,-9) and (2,1). Also find the coordinates of the points of division.

Explanation

To solve the problem, we need to find the ratio in which the line \(2x + 3y - 5 = 0\) divides the line segment joining the points \(A(8, -9)\) and \(B(2, 1)\). We will also find the coordinates of the point of division.

### Step 1: Assign Coordinates
Let the coordinates of point \(A\) be \(A(8, -9)\) and the coordinates of point \(B\) be \(B(2, 1)\).

### Step 2: Assume the Ratio
Assume the line divides the segment \(AB\) in the ratio \(m:n\). We can express the coordinates of the point \(M\) that divides \(AB\) in the ratio \(m:n\) using the section formula:
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