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For the following probability distributi...

For the following probability distribution determine standard deviation of the random variable X.

Text Solution

Verified by Experts

We have,

We know that, standard deviation of X=`sqrt(VarX)`
where, VarX=`E=(X^(2))-[E(X)]^(2)`
`therefore Var X=[0.8+4.5+4.8]-[0.4+1.5+1.2]^(2)`
`=10.1-(3.1)^(2)=10.01-9.61=0.49`
`therefore` Standard deviation of X =`sqrt(Var X)=sqrt(0.49)=0.7`
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