Two baised dice are thrown together. For the first die `P(6)=1/2` , other scores being equally likely while for the second die, `P(1)=2/5` and other scores are equally likely. Find the probability distribution of the number of ones seen.

Explanation

To find the probability distribution of the number of ones seen when two biased dice are thrown together, we can follow these steps:

### Step 1: Determine the probabilities for the first die

Given:
- \( P(6) = \frac{1}{2} \)

Since the total probability must equal 1, we can express the probabilities for the other outcomes (1, 2, 3, 4, 5) as equal. Let \( P(i) \) for \( i = 1, 2, 3, 4, 5 \) be \( p \).
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