Home
Class 12
MATHS
If X be a random variable taking values ...

If X be a random variable taking values `x_(1),x_(2),x_(3),….,x_(n)` with probabilities `P_(1),P_(2),P_(3)`,…..`P_(n)`, respectively. Then, Var (x) is equal to …….. .

Text Solution

Verified by Experts

Var (X) = `E(X)^(2)-[E(X)]^(2)`
=`underset(i=1)overset(n)SigmaX^(2)P(X)-"["underset(i=1)overset(n)SigmaXP(X)"]"^(2)`
`=SigmaP_(i)x_(i)^(2)-(SigmaP_(i)x i)^(2)`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|38 Videos
  • MATRICES

    NCERT EXEMPLAR ENGLISH|Exercise Solved example|101 Videos
  • RELATIONS AND FUNCTIONS

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|15 Videos

Similar Questions

Explore conceptually related problems

A random variable X takes values 0, 1, 2, 3,… with probability proportional to (x+1)((1)/(5))^x . P(Xge2) equals

A random variable X takes the values 0,1,2,3,..., with prbability PX(=x)=k(x+1)((1)/(5))^x , where k is a constant, then P(X=0) is.

If P(x) =x+3, then p(x)+p(-x) is equal to

Let X be a random variable which assumes values x_1, x_2, x_3,\ x_4 such that 2P(X=x_1)=3P(X=x_2)=P(X=x_3)=5P(X=x_4)dot Find the probability distribution of X.

If X is a Poisson variate and P(X=1)=2P(X=2) them P(X=3)=

A random variable X takes the values 0,1,2,3 and its mean = 1,3 .If P(X=3) =2P(X=1) and P(X=2) = 0.3 then P(X=0) is

The mean and variance of a random variable X having a binomial probability distribution are 6 and 3 respectively, then the probabiltiy P(X ge 2) is

The random variable takes the values 1,2,3,…….m. If P(X=n)=(1)/(m) to each n, then the variance of X is

If X follows Binomial distribution with parameters n=5, p and P(X=2)=9P(X=3), then p is equal to ……. .

For a binomial variate X , if n = 3 and 4P (X=1) = 3P (X=3) , then p (probability of success)