Energy of electron in first excited state in Hydrogen atom is -3.4eV. Find KE and PE of electron in the ground state.

Explanation

To find the kinetic energy (KE) and potential energy (PE) of the electron in the ground state of a hydrogen atom, we can follow these steps:

### Step 1: Understand the Energy Levels
The energy of an electron in a hydrogen atom is given by the formula:
\[ E_n = -\frac{E_0}{n^2} \]
where \(E_0 = 13.6 \, \text{eV}\) is the energy of the electron in the ground state (n=1) and \(n\) is the principal quantum number.
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