Energy gap in a p – n photodiode is 2.8 eV. Can it detect a wavelength of 6000 nm? Justify your answer.

Explanation

To determine whether a p-n photodiode with an energy gap of 2.8 eV can detect a wavelength of 6000 nm, we will follow these steps:

### Step 1: Understand the relationship between energy and wavelength
The energy of a photon can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)),
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