The electrical resistance of a column of `0.05 " mol " L^(-1)` NaOH solution of diameter 1 cm and length 50 cm is `5.55xx10^(3)" ohm "`.Calculate its resistivity,conductivity and molar conductivity.

The elctrical resistance of a column of 0.05 M N aOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^(3)ohm . Calculate its resisteivity , conductivity, and molar conductivity.

The elctrical resistance of a column of 0.05 M N aOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^(3)ohm . Calculate its resisteivity , conductivity, and molar conductivity.

(a) Define the following terms : (i) Limiting molar conductivity, (ii) Fuel cell (b) Resistance of a conductivity cell filled with 0.1 molL^(-1)KCl solution is 100 Ohm. If the resistance of the same cell when filled with 0.2 mol L^(-1)KCl solution is 520 Ohm , calculate the conductivity and molar conductivity of 0.2 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29xx10^(-1) Scm^(-1) .

Resistance of a conductivity cell filled with 0.1 M KCl is 100 ohm. If the resistence of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. Conductivity of 0.1 KCl solution is 1.29xx10^(-2)" ohm "^(-1)cm^(-1) .

The conductivity of a 0.01 M solution of acetic acid at 298 k is 1.65xx10^(-4) S cm ^(-1) . Calculate molar conductivity (wedge_(m)) of the solution.

The conductivity of a 0.01 M solution of acetic acid at 298 k is 1.65xx10^(-4) S cm ^(-1) . Calculate molar conductivity (wedge_(m)) of the solution.

The resistance of a 0.01N solution of an electroyte was found to 210 ohm at 298K using a conductivity cell with a cell constant of 0.88 cm^(-1) . Calculate specific conductance and equilvalent conductance of solution.

The conductivity of 0.001 "mol" L^(-1) solution of CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . "Given" lambda^(@) (H^(+)) = 349.6 "S" cm^(2) "mol"^(-1) " and " lambda^(0) (CH_(3)COO^(-)) = 40.9 "S" cm^(2) per mol)

The resistance of a 0.01N solution of an electrolyte was found to 210 ohm at 298K using a conductivity cell with a cell constant of 0.88 cm^(-1) . Calculate specific conductance and equivalent conductance of solution.

The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.