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State Gauss's theorem in electrostatics...

State Gauss's theorem in electrostatics. Apply this theorem to derive an expression for electric field intensity at a point outside a uniformly charged thin spherical shell.

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### Step-by-Step Solution **Step 1: State Gauss's Law** Gauss's Law in electrostatics states that the total electric flux (Φ_E) out of a closed surface is equal to the charge (Q_enc) enclosed within that surface divided by the permittivity of free space (ε₀). Mathematically, it can be expressed as: \[ \Phi_E = \oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{\text{enc}}}{\varepsilon_0} \] where: ...
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