Calculate the energy released in MeV in the following nuclear reaction :
`._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u`
Mass of `._(90)^(238)Th=234.043630 u`
Massof `._(2)^(4)He=4.002600 u`
`1u = 931.5 MeV//c^(2)]`

Explanation

To calculate the energy released in the nuclear reaction:

\[ _{92}^{238}U \rightarrow _{90}^{234}Th + _{2}^{4}He + Q \]

we will follow these steps:

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