The ground state energy of hydrogen atom is -13.6 eV.
(i) What is the kinetic energy of an electron in the `2^(nd)` excited state ?
(ii) If the electron jumps to the ground state from the `2^(nd)` excited state, calculate the wavelength of the spectral line emitted.

Explanation

To solve the question step by step, we will break it down into two parts as stated in the question.

### Part (i): Kinetic Energy of an Electron in the 2nd Excited State

1. **Identify the Energy Levels**:
The ground state energy of the hydrogen atom is given as \( E_1 = -13.6 \, \text{eV} \). The energy of the hydrogen atom in any state \( n \) is given by the formula:
\[
E_n = \frac{-13.6}{n^2} \, \text{eV}
...