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A wire of 15 Omega resistance is gradual...

A wire of `15 Omega` resistance is gradually stretched to double in original length. it is then cut into two equal parts .These parts are then connected in parallel across a `3.0` volt battery. Find the current draw from the battery .

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To solve the problem step by step, we will follow the instructions provided in the video transcript and elaborate on each step. ### Step 1: Understand the Given Data - The initial resistance of the wire, \( R = 15 \, \Omega \) - The wire is stretched to double its original length. - The voltage of the battery, \( V = 3.0 \, \text{volts} \) ### Step 2: Calculate the New Resistance After Stretching ...
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