In Young's double slit experiment the two slits 0.12 mm apart are illuminated by monochromatic light of wavelength 420 nm. The screen is 1.0 m away from the slits .
(a) Find the distance of the second (i) bright fringe , (ii) dark fringe from the central maximum .
(b) How will the fringe pattern change if the screen is moved away from the slits ?

Explanation

### Step-by-Step Solution

**Given Data:**
- Distance between the slits (d) = 0.12 mm = \(0.12 \times 10^{-3}\) m
- Wavelength of light (λ) = 420 nm = \(420 \times 10^{-9}\) m
- Distance from slits to screen (D) = 1.0 m

#### Part (a): Finding Distances from Central Maximum
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