Two wavelengths of sodium light 590 nm and 596 nm are used, in turn, to study the diffraction taking place at a single slit of aperture `2 xx 10^(-4)m.` The distance between the slit and the screen is 1.5 m. Calculate the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases.

Explanation

To solve the problem, we need to calculate the separation between the positions of the first maxima of the diffraction pattern obtained using two different wavelengths of sodium light.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Wavelength 1 (\(\lambda_1\)) = 590 nm = \(590 \times 10^{-9}\) m = \(5.90 \times 10^{-7}\) m
- Wavelength 2 (\(\lambda_2\)) = 596 nm = \(596 \times 10^{-9}\) m = \(5.96 \times 10^{-7}\) m
- Distance from the slit to the screen (D) = 1.5 m
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