A proton and deuteron are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-Broglie wavelength associated with it, and (b) less momentum? Give reasons to justify your answer.

Explanation

To solve the problem step by step, we will analyze the de Broglie wavelength and momentum of a proton and a deuteron that are accelerated through the same potential.

### Step 1: Understanding the de Broglie wavelength
The de Broglie wavelength (\( \lambda \)) of a particle is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle.
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