A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and (b) less kinetic energy? justify your answer.

Explanation

To solve the question, we need to analyze the de Broglie wavelength and kinetic energy of a proton and an alpha particle when they are accelerated through the same potential difference.

### Step-by-Step Solution:

1. **Understanding de Broglie Wavelength**:
The de Broglie wavelength (λ) of a particle is given by the formula:
\[
\lambda = \frac{h}{\sqrt{2mK}}
...