A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and (b) less kinetic energy? justify your answer.

Explanation

To solve the problem, we will analyze the de Broglie wavelength and kinetic energy of a proton and an alpha particle that are accelerated through the same potential difference.

### Step 1: Understanding the relationship between kinetic energy and accelerating potential
When a charged particle is accelerated through a potential difference \( V_0 \), the work done on the particle is converted into kinetic energy (KE). The kinetic energy can be expressed as:
\[ KE = qV_0 \]
where \( q \) is the charge of the particle.
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