A parallel plate capacitor of capacitane C is charged to a potential V. It is then connected to another uncharged capacitor with the same capacitance. Find out the ratio of the energy stored in the combined system to that stored initially in the single capacitor.

Explanation

To solve the problem step by step, let's analyze the situation involving the capacitors.

### Step 1: Calculate the initial energy stored in the charged capacitor.
The energy stored in a capacitor is given by the formula:
\[ U_1 = \frac{Q^2}{2C} \]
where \( Q \) is the charge on the capacitor and \( C \) is the capacitance.
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