An electron microscope uses electrons accelerated by a voltage of `50kV`. Determine the De Broglie wavelength associated with the electrons. If other factors ( such as numerical aperture, etc.) are taken to be roughly the same, how does the resolving power of an electron microscope compare with that of an optical microscope which uses yellow light?

Explanation

To solve the problem, we need to determine the De Broglie wavelength of electrons accelerated by a voltage of 50 kV and then compare the resolving power of the electron microscope with that of an optical microscope using yellow light.

### Step-by-Step Solution:

**Step 1: Calculate the kinetic energy of the electrons.**
The kinetic energy (K.E.) of an electron accelerated through a potential difference (V) is given by:
\[ K.E. = q \cdot V \]
where:
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