A biconcave lens made of a transparent material of refractive index 1.5 is immersed in water of refractive index 1.33. Will the lens behave as a converging or a diverging lens? Give reason.

Explanation

To determine whether a biconcave lens behaves as a converging or diverging lens when immersed in water, we can follow these steps:

### Step 1: Identify the refractive indices
- The refractive index of the lens (material) is given as \( n_l = 1.5 \).
- The refractive index of the surrounding medium (water) is given as \( n_w = 1.33 \).

### Step 2: Compare the refractive indices
- Since \( n_l (1.5) > n_w (1.33) \), the lens is made of a material that has a higher refractive index than the surrounding water.
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