The electon, in a hydrogen atom, is in its second excited state. Calculate the wavelength of the lines in the Lyman series, that can be emitted through the permisible transitions of this electron.
Given the value of Rydberg constant, `R=1.1xx10^(7)m^(-1))`

Explanation

To solve the problem of calculating the wavelengths of the lines in the Lyman series emitted from a hydrogen atom when the electron is in its second excited state, we will follow these steps:

### Step 1: Identify the Energy Levels
The second excited state of a hydrogen atom corresponds to the principal quantum number \( n = 3 \) (since the ground state is \( n = 1 \), the first excited state is \( n = 2 \), and the second excited state is \( n = 3 \)).

### Step 2: Determine Possible Transitions
In the Lyman series, transitions occur to the ground state \( n = 1 \). The possible transitions from the second excited state \( n = 3 \) are:
1. From \( n = 3 \) to \( n = 1 \)
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