A circualr coil, having 100 tures of wire, of readius (nearly) 20cm each, lies in the XY plane with its centre at the origin of co-ordinates. Find the magnetic field, at the point `(0,0,20sqrt3Cm)`, when this coil carries a current of `((2)/(pi))A`.

Explanation

To find the magnetic field at the point (0, 0, 20√3 cm) due to a circular coil with 100 turns of wire and a radius of 20 cm carrying a current of (2/π) A, we can follow these steps:

### Step 1: Convert Units
Convert all measurements to SI units.
- Radius \( R = 20 \, \text{cm} = 0.2 \, \text{m} \)
- Height \( Z = 20\sqrt{3} \, \text{cm} = 0.2\sqrt{3} \, \text{m} \)
- Current \( I = \frac{2}{\pi} \, \text{A} \)

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