The temperature coefficient of resistance for two material A and B are `0.0031^(@)C^(-1)` and `0.0068^(@)C^(-1)` respectively .Two resistance `R_(1) and R_(2)` made from material A and B respectively . Have resistance of `200 Omega` and `100 Omega` at `0^(@)C`. Show as a diagram the colour cube of a carbon resistance that would have a resistance equal to the series combination of `R_(1) and R_(2)` at a temperature of `100^(@)C` (Neglect the ring corresponding to the tolerance of the carbon resistor)

Explanation

To solve the problem step by step, we will calculate the resistance of each material at 100°C, find the total resistance when they are in series, and then determine the color code for the equivalent carbon resistor.

### Step 1: Calculate the resistance of R1 at 100°C
The formula for resistance at a temperature \( T \) is given by:
\[ R_T = R_0 (1 + \alpha \Delta T) \]
where:
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