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A nucleus with mass number A =240 a...

A nucleus with mass number A =240 and BE`//`A = 7.6 Me V breaks into two fragments each of A =120 with `BE//A ` =8.5 Me V .Calculate the released energy .

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To solve the problem, we need to calculate the energy released when a nucleus with mass number \( A = 240 \) and binding energy per nucleon \( BE/A = 7.6 \, \text{MeV} \) breaks into two fragments, each with mass number \( A = 120 \) and binding energy per nucleon \( BE/A = 8.5 \, \text{MeV} \). ### Step 1: Calculate the total binding energy of the original nucleus (B1) The total binding energy \( B_1 \) of the original nucleus can be calculated using the formula: \[ B_1 = \left( \frac{BE}{A} \right) \times A ...
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