Home
Class 12
PHYSICS
Two cells of emfs 1.5 V and 2.0v hav...

Two cells of emfs 1.5 V and 2.0v having internal resistance 0.2`Sigma` and 0.3 `Sigma` respectively are connected in parallel . Calculate the emf and internal resistance of the equivalent cell .

Text Solution

AI Generated Solution

To solve the problem of finding the equivalent EMF and internal resistance of two cells connected in parallel, we will follow these steps: ### Step 1: Identify the given values - EMF of cell 1 (E1) = 1.5 V - Internal resistance of cell 1 (R1) = 0.2 Ω - EMF of cell 2 (E2) = 2.0 V - Internal resistance of cell 2 (R2) = 0.3 Ω ...
Promotional Banner

Topper's Solved these Questions

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise Section -C|7 Videos

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise Section-E|17 Videos

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise Section -A|14 Videos

  • SAMPLE PAPER 2019

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

Two cells of 1.5 V and 2 V , having internal resistances of 1Omega and 2Omega respectively, are connected in parallel so as to read the current in the same direction through an external resistance of 5 Omega . The current in the external resistance will be

If three cell are connected in parallel then equivalent emf……. and equivalent internal resistance is …..

If n cells each of emf E and internal resistance rare connected in parallel, then the total emf and internal resistances will be

Two cells of emfs epsilon_(1)and epsilon_(2) and internal resistances r_(1)and r_(2) respectively are connected in parallel . Obtain expressions for the equivalent (i) resistance and , (ii) emf of the combination.

Five cells each of emf E and internal resistance r are connecte in series. Due to oversight one cell is connected wrongly . The equivalent emf and internal resistance of the combination is

In the circuit shown in fig. the cell has emf 10V and internal resistance 1 Omega

Two cells having an internal resistance of 0.2 Omega and 0.4 Omega are connected in parallel (same polarity) the voltage across the battery is 1.5 V. If the emf of one cell is 1.2 V, then the emf of second cell is

Two cells of emf E_(1) and E_(2) have internal resistance r_(1) and r_(2) . Deduce an expression for equivalent emf of their parallel combination.

24 cells, each of emf 1.5V and internal resistance is 2Omega connected to 12Omega series external resistance. Then,

Maximum current produced by a cell of emf 10 V and internal resistance 2 Omega is