A parallel plate capacitor of capacitance C is charged to a potential V by a battery. Without disconnecting the battery, distance between the plates of capacitor is tripled and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ?
(a) Capacitance of capacitor
(b) Charge on capacitor
(c ) Energy density of capacitor.

Explanation

To solve the problem step by step, we will analyze the effects of tripling the distance between the plates of a capacitor and introducing a dielectric medium with a dielectric constant \( K = 10 \).

### Step 1: Calculate the New Capacitance
The capacitance \( C \) of a parallel plate capacitor is given by the formula:
\[ C = \frac{\varepsilon_0 A}{D} \]
where:
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