A capacitor of capacitance `C_(1)` is charged to a potential `V_(1)` while another capacitor of capacitance `C_(2)` is charged to a potential difference `V_(2)` . The capacitors are now disconnected from their respective charging batteries and connected in parallel to each other .
(a) Find the total energy stored in the two capacitors before they are connected.
(b) Find the total energy stored in the parallel combination of the two capacitors.
(c ) Explain the reason for the difference of energy in parallel combination in comparison to the total energy before they are connected.

Explanation

Let's solve the question step by step.

### Part (a): Total Energy Stored Before Connection

1. **Energy in Capacitor C1**: The energy stored in a capacitor is given by the formula:
\[ E_1 = \frac{1}{2} C_1 V_1^2 \]
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