A bar magnet of magnetic moment 6 `J//T` is aligned at `60^(@)` with a uniform external magnetic field of 0.44 T. Calculate (a) the work done in turning the magnet to align its magnetic moment (i) normal to the magnetic field, (ii) opposite to the magnetic field, and (b) the torque on the magnet in the final orientation in case (ii).

Explanation

To solve the problem step by step, we will calculate the work done in two scenarios: (a) when the magnet is turned to align its magnetic moment normal to the magnetic field, and (b) when it is turned to align opposite to the magnetic field. We will also find the torque on the magnet in the final orientation for case (ii).

### Given Data:
- Magnetic moment, \( m = 6 \, \text{J/T} \)
- External magnetic field, \( B = 0.44 \, \text{T} \)
- Initial angle, \( \theta_i = 60^\circ \)

### Part (a): Work Done
...