Home
Class 12
PHYSICS
The graph shows variation of stopping po...

The graph shows variation of stopping potential `V_(0)` versus frequency of incident radiation v for two photosensitive metals A and B. Which of the two metals has higher threshold frequency and why?

Text Solution

Verified by Experts

Threshold frequency of Q is more than that of P, as wave length is inversely proportional to frequency

`C=v lamda`
threshold wave length will be smaller for Q.
Promotional Banner

Topper's Solved these Questions

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise SECTION - B|7 Videos

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise SECTION - C|10 Videos

  • SAMPLE PAPER 2019

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

The graph shows variation of stopping potential V_(0) versus frequency of incident radiation v for two photosensitive metals A and B . Which of two metals has higher threshold frequency and why?

Sketch the graphs, showing the variation of stopping potential V_s with frequency v of the incident radiations for two photosensitive materials A and B having threshold frequencies v_0gtv'_0 respectively. (i) which of the two metals A or B has higher work function? (ii) What information do you get from the slope of the graphs? (iii) What does the value of the intercept of graph A on the potential axis represent?

Fig. shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosensitive metal P and Q: (i) Explain which metal has smaller threshold wavelength (ii) Explain, giving reason, which metal emits photoelectrons having smaller kinetic energy, for the same wavelength of incident radiation. (iii) If the distance between the light source and metal P is doubled, how will the stopping potential change.

In the study of a photoelectric effect the graph between the stopping potential V and frequency nu of the incident radiation on two different metals P and Q is shown in fig. (i) which one of two metals have higher threshold frequency (ii) Determine the work function of the metal which has greater value (iii) Find the maximum kinetic energy of electron emitted by light of frequency 8xx10^(14) Hz for this metal.

The slope of the graph drawn between stopping potential and frequency of incident radiation will be

The graph between the stopping potential V_(0) and frequency v for two different metal plates P and Q are shown in the figure. Which of the metals has greater threshold wavelength and work function.

Plot a graph showing the variation of stopping potential with the frequency of incident radiation for two different photosensitive having work functions W_1 and W_2(W_1 gt W_2) . On what factors does the (i) slope and (ii) intercept of the lines depend ?

Figure shows the graph of stopping potential verus that frequency of a photosensitive metal. The plank's constant and work funcation of the metal are

Explain giving reasons for the following : (a) Photoelectric current in a photocell increases with the increase in intensity of the incident radiation. (b) The stopping potential V_0 varies linearly with the frequency nu of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces. (c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.