In triangle `A B C ,(sinA+sinB+sinC)/(sinA+sinB-sinC)` is equal to

Explanation

To solve the problem \(\frac{\sin A + \sin B + \sin C}{\sin A + \sin B - \sin C}\) in triangle \(ABC\), we can follow these steps:

### Step 1: Understand the relationships in a triangle
In any triangle, the angles \(A\), \(B\), and \(C\) satisfy the relationship \(A + B + C = \pi\). This will help us express one angle in terms of the others.

### Step 2: Rewrite the numerator
The numerator is \(\sin A + \sin B + \sin C\). We can use the sine addition formula:
\[
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