The number of values of `x` in the in interval `[0,5pi]` satisfying the equation `3sin^2x-7sinx+2=0` is 0 (b) 5 (c) 6 (d) 10

Explanation

To solve the equation \(3\sin^2 x - 7\sin x + 2 = 0\) for the number of values of \(x\) in the interval \([0, 5\pi]\), we can follow these steps:

### Step 1: Rewrite the Equation
We start with the quadratic equation in terms of \(\sin x\):
\[ 3\sin^2 x - 7\sin x + 2 = 0 \]

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