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If 10! =2^p .3^q .5^r .7^s, then (A) 2q ...

If `10! =2^p .3^q .5^r .7^s`, then `(A)` `2q = p` `(B)` `pqrs = 64` `(C)` number of divisors of `10!` is `280` `(D)` number of ways of putting `10!` as a product of two natural numbers is `135`

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CENGAGE ENGLISH-PERMUTATIONS AND COMBINATIONS-All Questions
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  2. Number of ways in which 30 identical things are distributed among six ...

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  3. If 10! =2^p .3^q .5^r .7^s, then (A) 2q = p (B) pqrs = 64 (C) number...

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