If `vece_(1),vece_(2),vece_(3)and vecE_(1),vecE_(2),vecE_(3)` arwe two sets of vectors such that `vece_(1).vecE_(j)=1, if and vece_(i).vecE_(j)=0 andif i nej, " the prove that " [vece_(1)vece_(2)vece_(3)][vecE_(1)vecE_(2)vecE_(3)]=1`

If vece_(1) = ( 1,1,1) and vece_(2) = ( 1,1,-1) and veca and vecb are two vectors that vece_(1) = 2veca +vecb and vece_(2) veca + 2vecb then angle between veca and vecb is

How are electric vector (vecE) , magnetic vector (vecB) velocity vector (vecC) oriented in an electromagnetic wave?

How are electric vector (vecE), magnetic vector (vecB) velocity vector (vecc) oriented in an electromagnetic wave?

A Gaussian surface S encloses two charges q_(1)= q and q_(2) = -q the field at p is where vecE_(1), vecE_(2)and vecE_(3) are the field contributed by q_(1),q_(2)and q_(3)at P respectively.

[vecaxx vecb " " vecc xx vecd " " vecexx vecf] is equal to (a) [veca vecb vecd] [vecc vece vecf]-[veca vecb vecc] [vecd vece vecf] (b) [veca vecb vece ] [vecf vecc vecd] - [veca vecb vecf] [vece vecc vecd] (c) [vecc vecd veca] [vecb vece vecf] - [veca vecd vecb] [vecavece vecf] (d) [veca vecc vece] [vecb vecd vecf]

if vecE=E_(0)cos(kz)cos(omegat)hati then vec(B) for electromagentic wave is

A dipole of moment vecp is placed in a uniform electric field vecE . The force on the dipole is vecF and the torque is vec(tau)

An electron projectes with velocity vecv=v_(0)hati in the electric field vecE=E_(0)hatj . There the path followed by the electron E_(0) .

The net field vecE due to the uniformly charged rod at P makes angles theta_(1) and theta_(2) with AP and BP respectively. Then find the value of theta_(1)//theta_(2)