`a_1, a_2, a_3, in R-{0}` and `a_1+a_2cos2x+a_3sin^2x=0` for all `x in R ,` then

a_1, a_2, a_3, in R-{0} and a_1+a_2cos2x+a_3sin^2x=0fora l lx in R , then

a_1, a_2, a_3, in R-{0} and a_1+a_2cos2x+a_3sin^2x=0fora l lx in R , then (a)vector vec a=a_1 hat i+a_2 hat j+a_3 hat ka n d vec b=4 hat i+2 hat j+ hat k are perpendicular to each other (b)vector vec a=a_1 hat i+a_2 hat j+a_3 hat ka n d vec b=- hat i+ hat j+2 hat k are parallel to each other (c)vector vec a=a_1 hat i+a_2 hat j+a_3 hat k is of length sqrt(6) units, then one of the ordered triple (a_1, a_2, a_3)=(1,-1,-2) (d)are perpendicular to each other if 2a_1+3a_2+6a_3=26 ,t h e n|a_1 hat i+a_2 hat j+a_3 hat k|i s2sqrt(6)

The number of all the possible triplets (a_1,a_2,a_3) such that a_1+a_2cos(2x)+a_3sin^2(x)=0 for all x is (a) 0 (b) 1 (c) 3 (d) infinite

Three distinct numbers a_1 , a_2, a_3 are in increasing G.P. a_1^2 + a_2^2 + a_3^2 = 364 and a_1 + a_2 + a_3 = 26 then the value of a_10 if a_n is the n^(th) term of the given G.P. is: A. 2.3^9 B. 3^9 C. 2.3^(10) D. 3^(12)

If a_1, a_2, a_3,.....a_n are in H.P. and a_1 a_2+a_2 a_3+a_3 a_4+.......a_(n-1) a_n=ka_1 a_n , then k is equal to

Let log_2N=a_1+b_1,log_3N=a_2+b_2 and log_5N=a_3+b_3 , where a_1,a_2,a_3notin1 and b_1,b_2 b_3 in [0,1) . If a_1=6,a_2=4 and a_3=3 ,the difference of largest and smallest integral values of N, is

If a_1,a_2,a_3, ,a_n are in A.P., where a_i >0 for all i , show that 1/(sqrt(a_1)+sqrt(a_2))+1/(sqrt(a_2)+sqrt(a_3))+ ..+1/(sqrt(a_(n-1))+sqrt(a_n))=(n-1)/(sqrt(a_1)+sqrt(a_n))dot

If a_1,a_2,a_3, ,a_n are in A.P., where a_i >0 for all i , show that 1/(sqrt(a_1)+sqrt(a_2))+1/(sqrt(a_2)+sqrt(a_3))++1/(sqrt(a_(n-1))+sqrt(a_n))=(n-1)/(sqrt(a_1)+sqrt(a_n))dot

Let a_1=0 and a_1,a_2,a_3 …. , a_n be real numbers such that |a_i|=|a_(i-1) + 1| for all I then the A.M. Of the number a_1,a_2 ,a_3 …., a_n has the value A where : (a) A lt -1/2 (b) A lt -1 (c) A ge -1/2 (d) A=-2

If a_1,a_2,a_3, ,a_n are in A.P., where a_i >0 for all i , show that 1/(sqrt(a_1)+sqrt(a_2))+1/(sqrt(a_1)+sqrt(a_3))++1/(sqrt(a_(n-1))+sqrt(a_n))=(n-1)/(sqrt(a_1)+sqrt(a_n))dot