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Solve(1//2)^(x^(2)-2x) lt 1//2....

Solve`(1//2)^(x^(2)-2x) lt 1//2`.

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We have `(1//2)^(x^(2)-2x) lt (1//2)^(2)" "(.:'" base, "1//2 lt 0)`
It means ` x^(2) - 2x gt 2 `
` rArr (x-(1+sqrt3))(x-(1-sqrt3)) gt 0`
` rArr x gt 1+ sqrt3 or x lt 1-sqrt3`
` rArr x in ( - infty, 1-sqrt3)cup (1+sqrt3, infty) `
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CENGAGE ENGLISH-LOGARITHM AND ITS PROPERTIES-ILLUSTRATION 1.4
  1. Solve(1//2)^(x^(2)-2x) lt 1//2.

    Text Solution

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