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Solve 4^(log(2)logx)=logx-(logx)^(2)+1 (...

Solve `4^(log_(2)logx)=logx-(logx)^(2)+1` (base is e).

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To solve the equation \( 4^{\log_{2}(\log x)} = \log x - (\log x)^{2} + 1 \), we will follow these steps: ### Step 1: Rewrite the base We can express \( 4 \) as \( 2^2 \): \[ 4^{\log_{2}(\log x)} = (2^2)^{\log_{2}(\log x)} = 2^{2 \cdot \log_{2}(\log x)} = 2^{\log_{2}((\log x)^2)} \] ...
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CENGAGE ENGLISH-LOGARITHM AND ITS PROPERTIES-ILLUSTRATION 1.49
  1. Solve 4^(log(2)logx)=logx-(logx)^(2)+1 (base is e).

    Text Solution

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