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The `x , y , z` are positive real numbers such that `(log)_(2x)z=3,(log)_(5y)z=6,a n d(log)_(x y)z=2/3,` then the value of `(1/(2z))` is ............

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To solve the problem, we need to find the value of \( \frac{1}{2z} \) given the logarithmic equations involving \( x, y, z \). Let's break it down step by step. ### Step 1: Convert logarithmic equations to exponential form We are given three logarithmic equations: 1. \( \log_{2x} z = 3 \) 2. \( \log_{5y} z = 6 \) 3. \( \log_{xy} z = \frac{2}{3} \) Using the property of logarithms that states \( \log_a b = c \) implies \( b = a^c \), we can rewrite these equations in exponential form: 1. From \( \log_{2x} z = 3 \): \[ z = (2x)^3 = 8x^3 \] 2. From \( \log_{5y} z = 6 \): \[ z = (5y)^6 = 15625y^6 \] 3. From \( \log_{xy} z = \frac{2}{3} \): \[ z = (xy)^{\frac{2}{3}} = x^{\frac{2}{3}} y^{\frac{2}{3}} \] ### Step 2: Set the equations equal to each other Now we have three expressions for \( z \): 1. \( z = 8x^3 \) 2. \( z = 15625y^6 \) 3. \( z = x^{\frac{2}{3}} y^{\frac{2}{3}} \) We can set these equations equal to each other to find relationships between \( x \) and \( y \). ### Step 3: Equate the first two expressions for \( z \) From \( 8x^3 = 15625y^6 \): \[ \frac{x^3}{y^6} = \frac{15625}{8} \] This gives us a relationship between \( x \) and \( y \). ### Step 4: Equate the second and third expressions for \( z \) From \( 15625y^6 = x^{\frac{2}{3}} y^{\frac{2}{3}} \): \[ \frac{15625y^6}{y^{\frac{2}{3}}} = x^{\frac{2}{3}} \] This simplifies to: \[ 15625y^{\frac{16}{3}} = x^{\frac{2}{3}} \] ### Step 5: Substitute \( x \) and \( y \) in terms of \( z \) From the first equation, we can express \( x \) in terms of \( z \): \[ x = \left(\frac{z}{8}\right)^{\frac{1}{3}} = \frac{z^{\frac{1}{3}}}{2} \] From the second equation, we can express \( y \) in terms of \( z \): \[ y = \left(\frac{z}{15625}\right)^{\frac{1}{6}} = \frac{z^{\frac{1}{6}}}{5} \] ### Step 6: Substitute \( x \) and \( y \) into the third equation Substituting \( x \) and \( y \) into \( z = x^{\frac{2}{3}} y^{\frac{2}{3}} \): \[ z = \left(\frac{z^{\frac{1}{3}}}{2}\right)^{\frac{2}{3}} \left(\frac{z^{\frac{1}{6}}}{5}\right)^{\frac{2}{3}} \] ### Step 7: Simplify the equation This leads to: \[ z = \frac{z^{\frac{2}{9}}}{4} \cdot \frac{z^{\frac{1}{9}}}{25} \] Combining the powers of \( z \): \[ z = \frac{z^{\frac{2}{9} + \frac{1}{9}}}{100} = \frac{z^{\frac{3}{9}}}{100} = \frac{z^{\frac{1}{3}}}{100} \] ### Step 8: Solve for \( z \) Now we can solve for \( z \): \[ z^{\frac{2}{3}} = \frac{1}{100} \] Taking the cube root: \[ z = \left(\frac{1}{100}\right)^{\frac{3}{2}} = \frac{1}{1000} \] ### Step 9: Find \( \frac{1}{2z} \) Now we can find \( \frac{1}{2z} \): \[ \frac{1}{2z} = \frac{1}{2 \cdot \frac{1}{1000}} = \frac{1000}{2} = 500 \] ### Final Answer Thus, the value of \( \frac{1}{2z} \) is: \[ \boxed{500} \]

To solve the problem, we need to find the value of \( \frac{1}{2z} \) given the logarithmic equations involving \( x, y, z \). Let's break it down step by step. ### Step 1: Convert logarithmic equations to exponential form We are given three logarithmic equations: 1. \( \log_{2x} z = 3 \) 2. \( \log_{5y} z = 6 \) 3. \( \log_{xy} z = \frac{2}{3} \) ...
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