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The value of 6+ log(3//2) (1/(3sqrt2)...

The value of
` 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...))))` is ________.

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Verified by Experts

The correct Answer is:
4
Let ` sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))= y`
So, ` 4-1/(3sqrt2)y=y^(2)" "(y gt 0)`
` or y^(2)+1/(3sqrt2)y-4 = 0`
` or y = 8/(3sqrt2)`
So, the required value is
` 6+log_(3//2)(1/(3sqrt2)xx8/(3sqrt2))=6 + log_(3/2). 4/9= 6 - 2 = 4`.
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