Solve x >sqrt((z-5))-sqrt(9-z)>1,x in Z...

Solve `x >sqrt((z-5))-sqrt(9-z)>1,x in Zdot`

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`sqrt(x- 5 )-sqrt(9-x ) gt 1, ` is meaningful ,if
`x- 5 ge 0 " and "9 - x ge 0`
`rArr x in [ 5, 9]`
Thus , the integral values of x are 5,6,7,8,9 of these only x= 9 stisfies the given inequality .

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Solve `x >sqrt((z-5))-sqrt(9-z)>1,x in Zdot`

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