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Solve x + sqrt(x ) ge sqrt( x )-3...

Solve `x + sqrt(x ) ge sqrt( x )-3`

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To solve the inequality \( x + \sqrt{x} \geq \sqrt{x} - 3 \), we will follow these steps: ### Step 1: Simplify the inequality Start by isolating the terms involving \( \sqrt{x} \): \[ x + \sqrt{x} - \sqrt{x} \geq -3 \] ...
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