Solve `|(x-3)/(x+1)| le 1`

Explanation

To solve the inequality \( \left| \frac{x-3}{x+1} \right| \leq 1 \), we will break it down into two cases based on the definition of absolute value.

### Step 1: Remove the absolute value
The inequality \( \left| \frac{x-3}{x+1} \right| \leq 1 \) can be rewritten as two separate inequalities:
1. \( \frac{x-3}{x+1} \leq 1 \)
2. \( \frac{x-3}{x+1} \geq -1 \)

### Step 2: Solve the first inequality
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