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Solve ||x-2|-3|lt 5...

Solve `||x-2|-3|lt 5 `

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To solve the inequality \( ||x - 2| - 3| < 5 \), we will break it down step by step. ### Step 1: Remove the outer absolute value We start with the inequality: \[ ||x - 2| - 3| < 5 \] This can be rewritten as: \[ -5 < |x - 2| - 3 < 5 \] Since the left side of the inequality \(-5 < |x - 2| - 3\) is always true (absolute values are non-negative), we only need to focus on the right side: \[ |x - 2| - 3 < 5 \] ### Step 2: Solve the right side of the inequality Now, we add 3 to both sides: \[ |x - 2| < 8 \] ### Step 3: Remove the absolute value The inequality \( |x - 2| < 8 \) implies: \[ -8 < x - 2 < 8 \] ### Step 4: Solve the compound inequality Now, we can solve the compound inequality by adding 2 to all parts: \[ -8 + 2 < x < 8 + 2 \] This simplifies to: \[ -6 < x < 10 \] ### Step 5: Final solution Thus, the solution to the inequality \( ||x - 2| - 3| < 5 \) is: \[ x \in (-6, 10) \]

To solve the inequality \( ||x - 2| - 3| < 5 \), we will break it down step by step. ### Step 1: Remove the outer absolute value We start with the inequality: \[ ||x - 2| - 3| < 5 \] This can be rewritten as: ...
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